Let sum = Rs. $$100x$$ and rate of interest = $$r\%$$ Amount after 2 years = Rs. 1392 => Amount under simple interest = $$P+frac{P imes R imes T}{100}$$ => $$100x+frac{100x imes r imes2}{100}=1392$$ => $$100x+2rx=1392$$ => $$x(100+2r)=1392$$ -----------------(i) Similarly, after 3 years, => => $$100x+frac{100x imes r imes3}{100}=1488$$ => $$x(100+3r)=1488$$ --------------(ii) Dividing equation (ii) by (i), we get : => $$frac{100+3r}{100+2r}=frac{1488}{1392}$$ => $$139200+4176r=148800+2976r$$ => $$4176r-2976r=100(1488-1392)$$ => $$1200r=100 imes96$$ => $$r=frac{96}{12}=8\%$$ => Ans - (A)