1. ΔPQR is right angled at Q. If $$tan P = \frac{24}{7}$$, then what is the value of cos R ?
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By: anil on 05 May 2019 03.01 pm
Given : $$ an P$$ = $$frac{24}{7}$$ Also, $$ an P=frac{QR}{PQ}=frac{24}{7}$$ Let QR = 24 cm and PQ = 7 cm Thus, in $$ riangle$$ PQR, => $$(PR)^2=(PQ)^2+(QR)^2$$ => $$(PR)^2=(7)^2+(24)^2$$ => $$(PR)^2=49+576=625$$ => $$PR=sqrt{625}=25$$ cm To find : $$cos R=frac{QR}{PR}$$ = $$frac{24}{25}$$ => Ans - (B)
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