1. A mixture of 50 kg of cement and gravel contains 10% of gravel. How many kg of gravel must be added to make the gravel content 28% in the new mixture?
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By: anil on 05 May 2019 02.05 am
Quantity of gravel in 50 kg mixture = $$frac{10}{100} imes50=5$$ kg Let $$x$$ kg of gravel must be added in the mixture, => $$(x+5)=frac{28}{100} imes(x+50)$$ => $$100x+500=28x+1400$$ => $$100x-28x=1400-500$$ => $$72x=900$$ => $$x=frac{900}{72}=12.5$$ $$ herefore$$ 12.5kg of gravel must be added to make the gravel content 28% in the new mixture. => Ans - (C)
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