1. ΔUVW is right angled at V. If $$sec U = \frac{5}{3}$$, then what is the value of $$tan W$$ ?
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By: anil on 05 May 2019 03.00 pm
Given : $$sec U$$ = $$frac{5}{3}$$ Also, $$sec U=frac{UW}{UV}=frac{5}{3}$$ Let UW = 5 cm and UV = 3 cm Thus, in $$ riangle$$ UVW, => $$(VW)^2=(UW)^2-(UV)^2$$ => $$(VW)^2=(5)^2-(3)^2$$
=> $$(VW)^2=25-9=16$$ => $$VW=sqrt{16}=4$$ cm To find : $$ an W=frac{UV}{VW}$$ = $$frac{3}{4}$$ => Ans - (A)
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Given : $$sec U$$ = $$frac{5}{3}$$ Also, $$sec U=frac{UW}{UV}=frac{5}{3}$$ Let UW = 5 cm and UV = 3 cm Thus, in $$ riangle$$ UVW, => $$(VW)^2=(UW)^2-(UV)^2$$ => $$(VW)^2=(5)^2-(3)^2$$
=> $$(VW)^2=25-9=16$$ => $$VW=sqrt{16}=4$$ cm To find : $$ an W=frac{UV}{VW}$$ = $$frac{3}{4}$$ => Ans - (A)