1. In a mixture, unbroken and broken rice grains are in the ratio 3 : 2. How much fraction of the mixture must be drawn off and substituted with broken grains, so that the ratio of unbroken and broken grains becomes 1 : 1?
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By: anil on 05 May 2019 02.04 am
Let quantity of unbroken and broken rice grains be $$3$$ and $$2$$ units respectively. Let $$x$$ units of mixture is taken out => Unbroken rice grains in $$(5-x)$$ units of mixture = $$frac{3}{5}(5-x)$$ Similarly, after adding broken rice grains, => Broken rice grains in mixture = $$frac{2}{5}(5-x)+x$$ According to ques, => $$frac{frac{3}{5}(5-x)}{frac{2}{5}(5-x)+x}=frac{1}{1}$$ => $$3-frac{3}{5}x=2-frac{2}{5}x+x$$ => $$frac{3x}{5}-frac{2x}{5}+x=3-2$$ => $$frac{6x}{5}=1$$ => $$x=frac{5}{6}$$ $$ herefore$$ Required fraction = $$frac{frac{5}{6}}{5}=frac{1}{6}$$ => Ans - (B)
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