1. ΔABC is right angled at B. If $$cot A = \frac{8}{15}$$, then what is the value of $$cos C$$ ?
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By: anil on 05 May 2019 03.00 pm
Given : $$cot A$$ = $$frac{8}{15}$$ Also, $$cot A=frac{AB}{BC}=frac{8}{15}$$ Let AB = 8 cm and BC = 15 cm Thus, in $$ riangle$$ ABC, => $$(AC)^2=(AB)^2+(BC)^2$$ => $$(AC)^2=(8)^2+(15)^2$$ => $$(AC)^2=64+225=289$$ => $$AC=sqrt{289}=17$$ cm To find : $$cos C=frac{BC}{AC}$$ = $$frac{15}{17}$$ => Ans - (D)
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