1. The sum of the square of three consecutive odd numbers is 2195. Find the numbers.
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By: anil on 05 May 2019 02.03 am
Let the three consecutive odd numbers be $$(x-2),(x),(x+2)$$ According to ques, => $$(x-2)^2+(x)^2+(x+2)^2=2195$$ => $$(x^2-4x+4)+(x^2)+(x^2+4x+4)=2195$$ => $$3x^2+8=2195$$ => $$3x^2=2195-8=2187$$ => $$x^2=frac{2187}{3}=729$$ => $$x=sqrt{729}=27$$ $$ herefore$$ Consecutive odd numbers are = $$25,27,29$$ => Ans - (C)
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