1. In ΔDEF measure of angle E is 90o. If cot D = $$\frac{5}{12}$$, and DE = 1cm, then what is the length (in cm) of side EF?
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By: anil on 05 May 2019 03.00 pm
Given : DE = 1 cm and cot D = $$frac{5}{12}$$ To find : EF = ? Solution : In right $$ riangle$$ DEF, => $$cot(D)=frac{DE}{EF}$$ => $$frac{5}{12}=frac{1}{EF}$$ => $$EF=frac{12}{5} imes1=2.4$$ cm => Ans - (A)
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