1. Two equal circles pass through each other’s centre. If the radius of each cirlce is 5 cm,what is the length of the common chord?





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  • By: anil on 05 May 2019 01.59 am
    Let O be the mid point between the centres. So , AO=OB=2.5
    Let C be one of the intersecting points of the circles. AC=5
    OC= $$sqrt{AC^2 - OA^2}$$
    OC= $$sqrt{5^2 - 2.5^2}$$
    = $$frac{5sqrt{3}}{2}$$
    Length of cord = $$2 imesfrac{5sqrt{3}}{2}$$
    = $$5sqrt{3}$$
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