1. Side AB of rectangle of ABCD is divided into four equal parts by points X, Y, Z respectively. The ratio of the areas of Triangle XYC and the rectangle ABCD is ?
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By: anil on 05 May 2019 01.59 am
ratio of their areas = $$frac{frac{1}{2}bh}{LB}$$
= $$frac{frac{1}{2} imesfrac{1}{4}AB imes BC}{AB imes BC}$$
= 1: 8
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= $$frac{frac{1}{2} imesfrac{1}{4}AB imes BC}{AB imes BC}$$
= 1: 8