1. The least positive integer which is a perfect square and also divisible by each of 21, 36 and 66 is :
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By: anil on 05 May 2019 01.59 am
21 = 3 x 7 36 = $$3^2 x 2^2$$ 66 = 2 x 3 x 11 and hence minimum number divisible by these numbers and perfect square is $$3^2 imes 2^2 imes 7^2 imes 11^2$$ = 213444
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