1. In the following figure, O is the centre of the circle and XO is perpendicular to OY. If the area of the triangle XOY is 32, then the area of the circle is
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By: anil on 05 May 2019 01.58 am
Since, OX and OY are perpendicular and also radii of circle.
From, the area of triangle =12×OX×OY=12×OX×OY = 32
r2 = 2 × 32 = 64.
r = 8. ∴ The area of circle = πr2 = 64π
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From, the area of triangle =12×OX×OY=12×OX×OY = 32
r2 = 2 × 32 = 64.
r = 8. ∴ The area of circle = πr2 = 64π