1. A, 0, B are three points on a line segment and C is a point not lying on AOB. If ∠AOC = 40° and OX, OY are the internal and external bisectors of ∠AOC respectively, then ∠BOY is





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  • By: anil on 05 May 2019 01.58 am
    OX is the bisector of ∠AOC = 2 ∠COX.
    ∴ ∠BOC = 2 ∠COY
    ∴ ∠AOC + ∠BOC
    2∠COX + 2∠COY = 180°
    2(∠COX + ∠COY) = 180°
    2∠XOY = 180°
    ∠XOY = 90°
    ∴ ∠AOX + ∠XOY + ∠BOY = 180°
    ∠BOY = 180° - 20° - 90° = 70°.
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