1. In a right-angled triangle ABC, ∠ABC = 90°, AB = 5 cm and BC = 12 cm. The radius of the circumcircle of the triangle ABC is
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By: anil on 05 May 2019 01.57 am
In $$ riangle$$ABC => AC = $$sqrt{(AB)^2 + (BC)^2}$$ => AC = $$sqrt{5^2 + 12^2}$$ = $$sqrt{169}$$
=> AC = 13 cm In a right angled triangle, circumcentre lies on the mid point of hypotenuse. => circumradius = $$frac{AC}{2}$$ = $$frac{13}{2}$$ = 6.5 cm
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=> AC = 13 cm In a right angled triangle, circumcentre lies on the mid point of hypotenuse. => circumradius = $$frac{AC}{2}$$ = $$frac{13}{2}$$ = 6.5 cm