Equation : $$3x + 4y = 12$$ To find $$x$$-intercept, put $$y$$=0 => $$3x + 0 = 12$$ => $$x$$ = 4 Similarly to find $$y$$-intercept, we need to put $$x$$ = 0 => $$0 + 4y = 12$$ => $$y$$ = 3 Thus, the line passes through (4,0) in x-axis and (0,3) in y-axis Using, $$d = sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$$ => $$x_1 = 0 , x_2 = 4 , y_1 = 0 , y_2 = 3$$ => $$d = sqrt{4^2 + 3^2}$$ => $$d = sqrt{25} = 5$$