1. In ΔABC, a line through A cuts the side BC at D such that BD : DC = 4 :5. If the area of ΔABD = 60 cm , then the area of ΔADC is
Write Comment
Comments
By: anil on 05 May 2019 01.51 am
Let BD = 4$$x$$ and DC = 5$$x$$ Let height of the triangle be $$h$$ which will be same for both triangles ABD and ADC. Now, area of $$ riangle$$ABD = $$frac{1}{2} * BD * h$$ = 60 => $$frac{1}{2} * 4x * h$$ = 60 => $$xh$$ = 30 Now, area of $$ riangle$$ADC = $$frac{1}{2} * DC * h$$ = $$frac{1}{2} * 5x * h = frac{1}{2} * 5 * 30$$ = 75 $$cm^2$$
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use