1. In a trapezium ABCD, AB || CD, AB < CD, CD = 6 cm and distance between the parallel sides is 4 cm. If the area of ABCD is 16 cm2, then AB is





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  • By: anil on 05 May 2019 01.49 am
    Let AB = $$x$$ cm and CD = 6 cm Height of trapezium = $$h$$ = 4 cm Area of trapezium = $$frac{1}{2} imes $$ (sum of parallel sides) $$ imes$$ height => $$frac{1}{2} imes (x+6) imes 4=16$$ => $$x+6=frac{16}{2}=8$$ => $$x=8-6=2$$ cm => Ans - (B)
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