1. If 'O' is the incentre of the Δ PQR. If ∠POR = 115°,then value of ∠PQR is
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By: anil on 05 May 2019 01.49 am
Given : O is the incentre of $$ riangle$$ PQR and $$angle$$ POR = 115° To find : $$angle$$ PQR = $$ heta$$ = ? Incentre of a triangle = $$90^circ+frac{ heta}{2}$$ => $$115^circ=90^circ+frac{ heta}{2}$$ => $$frac{ heta}{2}=115^circ-90^circ=25^circ$$ => $$ heta=25^circ imes 2=50^circ$$ => Ans - (C)
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