1. A pilot in an aeroplane at an altitude of 200 m observes two points lying on either side of a river. If the angles of depression of the two points be 45° and 60°, then the width of the river is
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By: anil on 05 May 2019 01.48 am
Given : A is the aeroplane and AD = 200 m To find : Width of river = BC = ? Solution : In $$ riangle$$ ADC => $$tan(60^circ)=frac{AD}{DC}$$ => $$sqrt{3}=frac{200}{DC}$$ => $$DC=frac{200}{sqrt{3}}$$ m Similarly, in $$ riangle$$ ABD => $$tan(45^circ)=frac{AD}{DB}$$ => $$1=frac{200}{DB}$$ => $$DB=200$$ m $$ herefore$$ BC = BD + DC = $$(200 + frac{200}{sqrt{3}})$$ m => Ans - (A)
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