1. Three bottles of equal capacity have mixture of milk and water in ratio 5 : 7, 7 : 9 and 2 : 1 respectively. These three bottles are emptied into a large bottle. What is the percentage of milk in the new mixture?
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By: anil on 05 May 2019 01.47 am
Let the capacity of each bottle = 48 litres [L.C.M.(12,16,3)] Ratio of milk and water in the three bottles respectively = 5:7 , 7:9 , 2:1 Milk in 1st bottle = $$frac{5}{(5+7)} imes48=20$$ litres and water in 1st bottle = $$48-20=28$$ litres Similarly, milk in 2nd bottle = $$frac{7}{16} imes48=21$$ litres and water in 2nd bottle = $$48-21=27$$ litres Similarly, milk in 3rd bottle = $$32$$ litres and water = $$16$$ litres => Total milk = $$20+21+32=73$$ litres and total water = $$28+27+16=71$$ litres $$ herefore$$ Percentage of milk in the new mixture = $$frac{73}{(73+71)} imes100$$ = $$frac{7300}{144}=50.69 approx 50.7\%$$ => Ans - (D)
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