1. In ΔPQR, PQ = PR = 18 cm, AB and AC are parallel to lines PR and PQ respectively. If A is the mid-point of QR, then what is the perimeter (in cm) of quadrilateral ABPC?
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By: anil on 05 May 2019 01.46 am
PQ = PR = 18 cm and A is the mid point of QR AB is parallel to PR and AC is parallel to PQ, => BC is parallel to QR and B and C are mid point of PQ and PR respectively. => $$frac{PB}{PQ}=frac{BC}{QR}$$ => $$frac{BC}{QR}=frac{1}{2}$$ Thus, BC = $$frac{1}{2}$$ QR => PB = PC = BC = $$frac{18}{2}=9$$ cm Similarly, AB = AC = BC = 9 cm and ABPC is a parallelogeram. $$ herefore$$ Perimeter of ABPC = $$4 imes9=36$$ cm => Ans - (D)
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