Let the first term of an AP = $$a$$ and the common difference = $$d$$ 4th term of AP = $$A_4=a+3d=11$$ ----------(i) 7th term = $$A_7=a+6d=-4$$ --------(ii) Subtracting equation (i) from (ii), we get : => $$6d-3d=-4-11$$ => $$3d=-15$$ => $$d=frac{-15}{3}=-5$$ Substituting it in equation (i), => $$a=11-3(-5)=11+15=26$$ $$ herefore$$ 15th term = $$A_{15}=a+14d$$ = $$26+14(-5)=26-70=-44$$ => Ans - (B)