1. D and E are points on side AB and AC of ΔABC. DE is parallel to BC. If AD:DB = 2:5 and area of ΔADE is 8 cm sq, what is the area (in sq cm) of quadrilateral BDEC?





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  • By: anil on 05 May 2019 01.45 am
    (diagram) For ADE & ABC are similar , AD:AB = 2:7 for similar triangles  Ratio of sides = $$sqrt{ ext(ratio of areas)}$$ 2:7 = $$sqrt{ ext(ratio of areas)}$$ 4:49 = $$frac{area of ADE}{area of ABC}$$ 4:49 = $$frac{8}{area of ABC}$$
    area of ABC = 98 area of DBCE = area of ABC - area of ADE = 98 - 8 = 90 So the answer is option C.
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