1. The average of 8 numbers is A and the average of four of these is B. If the average of remaining four is C, then
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By: anil on 05 May 2019 01.41 am
The average 8 numbers is A => Sum of 8 numbers = 8A Let average of first four of these is B => Sum of first four = 4B Average of remaining four = C => Sum of last 4 = 4C Also, sum of first 4 numbers + Sum of last 4 numbers = Sum of all the 8 numbers => $$4B + 4C = 8A$$ Dividing both sides by 4, we get : => $$2A = B + C$$
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