1. The price of 8 books and 24 registers is Rs. 1760. If the price of one book is Rs. 124 more than the price of one register, what is the total price of 4 books and 2 registers ? (In Rs.)
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By: anil on 05 May 2019 01.40 am
Let price of 1 register = $$Rs. x$$ => Price of book = $$Rs. (x + 124)$$ Acc. to ques, => $$8 (x + 124) + 24x = 1760$$ => $$8x + 992 + 24x = 1760$$ => $$32x = 1760 - 992 = 768$$ => $$x = frac{768}{32} = 24$$ Thus, price of book = $$24 + 124 = 148$$ $$ herefore$$ Total price of 4 books and 2 registers = $$(4 imes 148) + (2 imes 24)$$ = $$592 + 48 = Rs. 640$$
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