1. Cost price of article A is 100/more than cost price of article B. Article A was sold at 40% profit and article B was sold at 40% loss. If the overall profit earned after selling both the articles is 5%, what is the cost price of article B ?
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By: anil on 05 May 2019 01.40 am
Let cost price of article B = $$Rs. 100x$$ => Cost price of article A = $$Rs. (100x + 100)$$ Total C.P. = $$Rs. (200x + 100)$$ Overall profit = 5% => S.P. = $$(200x + 100) + frac{5}{100} imes (200x + 100) = Rs. (210x + 105)$$ --------------(i) Article A was sold at 40% profit and article B was sold at 40% loss. => Selling price of article B = $$100x - frac{40}{100} imes 100x = Rs. 60x$$ Selling price of article A = $$(100x + 100) + frac{40}{100} imes (100x + 100)$$ = $$Rs. (140x + 140)$$ Total S.P. = $$Rs. (200x + 140)$$ -------------(ii) Equating equations (i) & (ii), we get : => $$210x + 105 = 200x + 140$$ => $$10x = 140 - 105 = 35$$ => $$x = frac{35}{10} = 3.5$$ $$ herefore$$ Cost price of article B = $$100 imes 3.5 = Rs. 350$$
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