1. If the positions corresponding to the multiples of five in the following alphabet are replaced by symbols and that of multiples of seven by digits, how many letters will be left ? A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
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By: anil on 05 May 2019 01.40 am
There are 26 alphabets positioned 1 to 26 Numbers which are multiples of 5 (till 26) = 5, 10, 15, 20, 25 Similarly, there will be 3 multiples of 7 Thus, total letters replaced by symbols and digits = 5 + 3 = 8 => Letters left = 26 - 8 = 18 => Ans - (B)
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