1. The sum of a series of 5 consecutive odd numbers is 225 The second number of this series is 15 less than the second lowest number of another series of 5 consecutive ever numbers. What is 60% of the highest number of this series of consecutive even numbers -
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By: anil on 05 May 2019 01.37 am
Let the five consecutive odd numbers in increasing order = $$(x-4) , (x-2) , (x) , (x+2) , (x+4)$$ Sum of these numbers = $$(x-4) + (x-2) + (x) + (x+2) + (x+4) = 225$$ => $$5x = 225$$ => $$x = frac{225}{5} = 45$$ Thus, the odd numbers are = 41 , 43 , 45 , 47 , 49 Let another series of even numbers in increasing order = $$(y-4) , (y-2) , (y) , (y+2) , (y+4)$$ Also, $$43 = (y - 2) - 15$$ => $$y = 43 + 15 + 2 = 60$$ Thus, highest number of the even series = 60 + 4 = 64 $$ herefore$$ 60% of 64 = $$frac{60}{100} imes 64 = 38.4$$
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