1. Rs. 6100 was partly invested in Scheme A at 10% p.a. compound interest (compounded annually) for 2 years and partly in Scheme B at 10% p.a. Simple interest for 4 years. Both the schemes give equal interests. How much was invested in Scheme A ?
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By: anil on 05 May 2019 01.36 am
Given that , Simple interest = compound interest so, $$frac{PTR}{100}=Q[(1+frac{r}{100})^{t}-1]$$ Let the amount invested in A be x. So , the amount invested in B will be (6100 - x) $$frac{(6100-x)4 imes10}{100}=x[(1+frac{10}{100})^{2}-1]$$ On solving , we get x = 4000 .
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