1. If the volume and curved surface area of a cylinder are 616 $$m^3$$ and 352 $$m^2$$ respectively what is the total surface area of the cylinder (in $$m^2$$)






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  • By: anil on 05 May 2019 01.36 am
    Volume of a cylinder=$$pi imes r^{2} imes h$$
    where $$r$$ and $$h$$ are the radius and height of the cylinder.
    $$pi imes r^{2} imes h$$ = $$616 m^{3}$$
    Curved Surface Area of Cylinder=$$2 imes pi imes r imes h$$=$$352 m^{2}$$
    $$pi imes r imes h$$=$$176$$
    Replacing $$pi imes r imes h$$ in Volume formula we get,
    $$ r imes 176$$=$$616$$
    $$r=3.5 m$$
    Total Surface Area = Curved Surface Area + 2$$ imes$$ Area of base
    =$$352 + 2 imes pi imes r^{2}$$
    =$$352 + 2 imes pi imes 3.5^{2}$$
    =$$352+77$$
    =$$429 m^{2}.$$
    Hence Option A is the correct answer.










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