1.
In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer
I. $$16x^{2} - 14x + 3 = 0$$
II. $$6y^{2} - 19y + 15 = 0$$
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By: anil on 05 May 2019 01.35 am
I : $$16x^{2} - 14x + 3 = 0$$ => $$16x^{2} - 8x - 6x + 3 = 0$$ => $$8x (2x - 1) -3 (2x - 1) = 0$$ => $$(8x - 3) (2x - 1) = 0$$ => $$x = frac{3}{8}, frac{1}{2}$$ II : $$6y^{2} - 19y + 15 = 0$$ => $$6y^{2} - 9y - 10y + 15 = 0$$ => $$3y (2y - 3) -5 (2y - 3) = 0$$ => $$(3y - 5) (2y - 3) = 0$$ => $$y = frac{5}{3}, frac{3}{2}$$ Since, both values of x < 1 and both values of y > 1. => y > x
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