1. A vessel contains a mixture of milk and water in the respective ratio of 10 : 3. Twenty-six litre of this mixture was taken out and replaced with 8 litre of water. If the resultant respective ratio of milk and water in the mixture was 5 : 2, what was the initial quantity of mixture in the vessel ? (in litre)






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  • By: anil on 05 May 2019 01.29 am
    Let quantity of Milk and water be M and W respectively.
    M : W =10 : 3
    3M=10W
    In 26 litre of mixture
    M =26(10/13) = 20 litre and
    W =26(3/13) = 6 litre
    8 litre of water is added.
    Resulting ratio of M and W is
    M-20 : W-6+8 = 5 : 2
    2(M-20) = 5(W+2)
    2M - 40 = 5W + 10
    Multiplyin all the terms by 2.
    4M - 80 = 10 W + 20
    Replacing 10W with 3M.
    4M - 80 = 3M + 20
    M = 100
    Hence W would be 30.
    Total quantity = 100+30 = 130.
    Option E is the correect answer.
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