1. Jar A has ‘x’ ml mixture of milk and water, of which 40% is water. Jar B also has mixture of milk and water, of which 20% is water. The quantity of mixture in Jar B is twice that of Jar A. If the content of Jar B is emptied into Jar A completely and the resultant quantity of milk in Jar A is 198 ml, what is the value of ‘x’ ?
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- By: anil on 05 May 2019 01.20 amTotal quantity of mixture in jar A = $$x$$ ml % of milk in jar A = 100 - 40 = 60% Quantity of milk in jar A = $$frac{60}{100} imes x = frac{3 x}{5}$$ ml Total quantity of mixture in jar B = $$2x$$ ml % of milk in jar B = 100 - 20 = 80% Quantity of milk in jar B = $$frac{80}{100} imes 2x = frac{8 x}{5}$$ ml => Total quantity of milk in jar A and B = $$frac{3 x}{5} + frac{8 x}{5} = 198$$ => $$frac{11 x}{5} = 198$$ => $$x = 198 imes frac{5}{11} = 18 imes 5$$ => $$x = 90$$ ml
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