1. Sheela walks a certain distance at (16/17)th of the usual speed and takes 5 minutes more than the usual time. Find the usual time taken. (in minutes)
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By: anil on 05 May 2019 01.13 am
Let usual speed = $$17$$ m/min and usual time taken = $$t$$ min => New speed = $$16$$ m/min and new time = $$(t+5)$$ min Also, speed is inversely proportional to time. => $$frac{17}{16}=frac{t+5}{t}$$ => $$17t=16t+80$$ => $$17t-16t=t=80$$ $$ herefore$$ Usual time taken = 80 minutes => Ans - (C)
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