1. Amir shared 775 gifts among 4 kids. The share of the first kid, twice the share of second kid, thrice the share of third kid and four times the share of fourth kid are all equal. Find the sum of gifts received by 1st kid and 2nd kid.
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- By: anil on 05 May 2019 01.13 amLet share of each kid be $$a,b,c,d$$ respectively. Then according to ques, => $$a=2b=3c=4d=k$$ => $$a=k$$ , $$b=frac{k}{2}$$ , $$c=frac{k}{3}$$ , $$d=frac{k}{4}$$ Thus, total = $$a+b+c+d=500$$ => $$k+frac{k}{2}+frac{k}{3}+frac{k}{4}=775$$ => $$k imes(frac{12+6+4+3}{12})=775$$ => $$k=775 imesfrac{12}{25}=372$$ $$ herefore$$ Sum of gifts received by 1st kid and 2nd kid = $$a+b=k+frac{k}{2}=3frac{k}{2}$$ = $$3 imesfrac{372}{2}=558$$ => Ans - (A)
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It is also known that:
1. In S, 60% of the surveyed kids were in G. Moreover, In S, all surveyed kids whose mothers had completed primary education were in school.
2. In NE, among the O kids, 50% had mothers who had dropped out before completing primary education.
3. The number of kids in G in NE was the same as the number of kids in G in W.What percentage of kids from S were studying in P?