1. Find the number of trailing Zeros in 243!





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  • By: anil on 05 May 2019 01.13 am
    Number of trailing zeroes = $$frac{243}{5}+frac{243}{25}+frac{243}{125}$$ = $$48+9+1=58$$     [Number will be round off to the lowest value] => Ans - (C)
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