1. A person cycles from hostel to college at a speed of 20 kmph and reaches 9.5 minutes late. If he cycles at a speed of 24 kmph and reaches early by 9.5 minutes, find the distance between hostel and college. (in km)
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By: anil on 05 May 2019 01.12 am
Let ideal time taken = $$t$$ hours Also, speed is inversely proportional to time. => $$frac{20}{24}=frac{t-frac{9.5}{60}}{t+frac{9.5}{60}}$$ => $$5t+frac{9.5}{12}=6t-frac{9.5}{10}$$ => $$6t-5t=frac{9.5}{12}+frac{9.5}{10}$$ => $$t=frac{47.5+57}{60}=frac{104.5}{60}$$ $$ herefore$$ Distance = speed $$ imes$$ time = $$20 imes(frac{104.5}{60}+frac{9.5}{60})$$ = $$frac{114}{3}=38$$ km => Ans - (C)
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