1. ________ is the highest-value seven-bit binary number.





Write Comment

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Tags
Show Similar Question And Answers
QA->Which number system is usually followed in a typical 32-bit computer ?....
QA->A computer with a 32 bit wide data bus implements its memory using 8 K x 8 static RAM chips. The smallest memory that this computer can have is:....
QA->The number of null branches for a binary tree with n nodes is:....
QA->Decimal equivalent of the signed binary number 11110101 in 1’s complement form is :....
QA->T he number of nodes in a complete binary tree of height n:....
MCQ-> The English alphabet is divided into five groups. Each group starts with the vowel and the consonants immediately following that vowel and the consonants immediately following that vowel are included in that group. Thus, the letters A, B, C, D will be in the first group, the letters E, F, G, H will be in the second group and so on. The value of the first group is fixed as 10, the second group as 20 and so on. The value of the last group is fixed as 50. In a group, the value of each letter will be the value of that group. To calculate the value of a word, you should give the same value of each of the letters as the value of the group to which a particular letter belongs and then add all the letters of the word: If all the letters in the word belong to one group only, then the value of that word will be equal to the product of the number of letters in the word and the value of the group to which the letters belong. However, if the letters of the words belong to different groups, then first write the value of all the letters. The value of the word would be equal to the sum of the value of the first letter and double the sum of the values of the remaining letters.For Example : The value of word ‘CAB’ will be equal to 10 + 10 + 10 = 30, because all the three letters (the first letter and the remaining two) belong to the first group and so the value of each letter is 10. The value of letter BUT = $$10 + 2 \times 40 + 2 \times 50 = 190$$ because the value of first letter B is 10, the value of T = 2 $$\times$$ 40 (T belongs to the fourth group) and the value of U = 2 $$\times$$ 50 (U belongs to the fifth group). Now calculate the value of each word given in questions 161 to 165 :AGE
 ....
MCQ-> Give an input a machine generates passcode step by step following certain rules as illustrated below: Input : talk seven 37 48 given 83 likely 62 Step I :37 talk seven 48 given 83 likely 62 Step III :37 talk 48 seven given 83 likely 62 Step IV :37 talk 48 seven given 62 likely given 83 Step V :37 talk 48 seven 62 likely 83 given Step V is the last step for this input. In the above following questions same logic as illustrated above is to be used.Step II for an input is ‘’23 working 48 32 park blossom 26 garden’’. What will be the fifth step ?
 ....
MCQ-> Mathematicians are assigned a number called Erdos number (named after the famous mathematician, Paul Erdos). Only Paul Erdos himself has an Erdos number of zero. Any mathematician who has written a research paper with Erdos has an Erdos number of 1.For other mathematicians, the calculation of his/her Erdos number is illustrated below:Suppose that a mathematician X has co-authored papers with several other mathematicians. 'From among them, mathematician Y has the smallest Erdos number. Let the Erdos number of Y be y. Then X has an Erdos number of y+1. Hence any mathematician with no co-authorship chain connected to Erdos has an Erdos number of infinity. :In a seven day long mini-conference organized in memory of Paul Erdos, a close group of eight mathematicians, call them A, B, C, D, E, F, G and H, discussed some research problems. At the beginning of the conference, A was the only participant who had an infinite Erdos number. Nobody had an Erdos number less than that of F.On the third day of the conference F co-authored a paper jointly with A and C. This reduced the average Erdos number of the group of eight mathematicians to 3. The Erdos numbers of B, D, E, G and H remained unchanged with the writing of this paper. Further, no other co-authorship among any three members would have reduced the average Erdos number of the group of eight to as low as 3.• At the end of the third day, five members of this group had identical Erdos numbers while the other three had Erdos numbers distinct from each other.• On the fifth day, E co-authored a paper with F which reduced the group's average Erdos number by 0.5. The Erdos numbers of the remaining six were unchanged with the writing of this paper.• No other paper was written during the conference.The person having the largest Erdos number at the end of the conference must have had Erdos number (at that time):
 ....
MCQ-> Study the given information carefully to answer the given questions. Seven athletes — M, N, 0, P, Q, R and S live on seven different floors of a building but not necessarily in the same order. The lowermost floor of the building is numbered one, the one above that is numbered two and so on till the topmost floor is numbered seven. Each one of them runs for a different distance in marathon 850 m, on till the topmost floor is numbered seven. Each one of them runs for a different distance in marathon 850 m, 1300 m, 2200 m, 2800 m, 3300 m, 4000 m and 4700 m, but not necessarily in the same order. The one who runs for 2200 m lives on floor numbered 3. Only one person lives between 0 and the one who runs for 2200 m. The one who runs for 4000 m lives immediately above O. Only one person lives between the one who runs for 4000 m and the one who runs for 1300 m. The number of people living between O and the one who runs for 1300 m is same as that between the one who runs for 4000 m and R. N lives on an odd numbered floor. N ran for 2000 m more than the one who lives on floor number 4. Only two people live between Q and the one who runs for 3300 m. The one who runs for 2800 m lives on one of the floors below Q but not on the floor number 2, Only two people live between M and S. The one who runs for 850 m lives immediately below M.How many people live between S and N?
 ....
MCQ-> In each of the following questions two rows of number are given. The resultant number in each row is to be worked out separately based on the following rules and the question below the row is to be answered. The operations of number progress from the left to right. Rules: (i) If an even number is followed by another even number they are to be added. (ii) If an even number is followed by a prime number, they are to be multiplied. (iii) If an odd number is followed by an even number, even number is to be subtracted from the odd number. (iv) If an odd number is followed by another odd number the first number is to be added to the square of the second number. (v) If an even number is followed by a composite odd number, the even number is to be divided by odd number.I. 84 21 13 II. 15 11 44 What is half of the sum of the resultants of the two rows ?....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
DMCA.com Protection Status Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions