1. Two identical circles intersect so that their centres, and the points at which they intersect, form a square of side 1 cm. The area in sq. cm of the portion that is common to the two circles is
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By: anil on 05 May 2019 02.29 am
We know that quad pmqn is a square of side 1. Area of the sector p-mqn is $$frac{45}{360}* pi *1*1$$ = $$frac{pi }{4}$$. Area of square = 1*1 = 1 Area of common portion = 2 * Area of sector - Area of square = 2 * $$frac{pi }{4}$$ - 1 = $$frac{pi }{2}$$ - 1
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We know that quad pmqn is a square of side 1. Area of the sector p-mqn is $$frac{45}{360}* pi *1*1$$ = $$frac{pi }{4}$$. Area of square = 1*1 = 1 Area of common portion = 2 * Area of sector - Area of square = 2 * $$frac{pi }{4}$$ - 1 = $$frac{pi }{2}$$ - 1