1. If $$ x = \sqrt[3]{7}+3$$ then the value of $$x^{3}-9x^{2}+27x-34$$ is:
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By: anil on 05 May 2019 03.31 am
Given : $$ x = sqrt[3]{7}+3$$ => $$x-3=sqrt[3]7$$ Cubing both sides, we get : => $$(x-3)^3=(sqrt[3]7)^3$$
=> $$x^3-27-3(3x)(x-3)=7$$ => $$x^3-27-9x^2+27x-7=0$$ => $$x^{3}-9x^{2}+27x-34=0$$ => Ans - (A)
By: anil on 05 May 2019 03.31 am
Given : $$ x = sqrt[3]{7}+3$$ => $$x-3=sqrt[3]7$$ Cubing both sides, we get : => $$(x-3)^3=(sqrt[3]7)^3$$
=> $$x^3-27-3(3x)(x-3)=7$$ => $$x^3-27-9x^2+27x-7=0$$ => $$x^{3}-9x^{2}+27x-34=0$$ => Ans - (A)
By: anil on 05 May 2019 03.31 am
Given : $$ x = sqrt[3]{7}+3$$ => $$x-3=sqrt[3]7$$ Cubing both sides, we get : => $$(x-3)^3=(sqrt[3]7)^3$$
=> $$x^3-27-3(3x)(x-3)=7$$ => $$x^3-27-9x^2+27x-7=0$$ => $$x^{3}-9x^{2}+27x-34=0$$ => Ans - (A)
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=> $$x^3-27-3(3x)(x-3)=7$$ => $$x^3-27-9x^2+27x-7=0$$ => $$x^{3}-9x^{2}+27x-34=0$$ => Ans - (A)