1. The sum of three consecutive natural numbers divisible by 3 is 45. The smallest number is:
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By: anil on 05 May 2019 02.28 am
Let the three consecutive natural numbers divisible by 3 be $$(3x-3),(3x),(3x+3)$$ Sum = $$(3x-3)+(3x)+(3x+3)=45$$ => $$9x=45$$ => $$x=frac{45}{9}=5$$ $$ herefore$$ Smallest number = $$3(5)-3=12$$ => Ans - (C)
Average of the numbers = $$frac{45}{3}=15$$ Thus, middle number is 15, hence the three numbers must be = 12, 15, 18
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Average of the numbers = $$frac{45}{3}=15$$ Thus, middle number is 15, hence the three numbers must be = 12, 15, 18