1. A candidate who gets 20% marks in an examination, fails by 30 marks. But if he gets 32% marks, he gets 42 marks more then the minimum pass marks. Find the pass percentage of marks.
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By: anil on 05 May 2019 02.19 am
Let maximum marks in the examination = $$100x$$ and passing marks = $$y$$ Marks secured by candidate = $$frac{20}{100} imes100x=20x$$ Thus, $$20x=y-30$$ -------------(i) Similarly, $$32x=y+42$$ -------------(ii) Subtracting equation (i) from (ii), we get : => $$32x-20x=42+30$$ => $$12x=72$$ => $$x=frac{72}{12}=6$$
Substituting it in equation (i), => $$y=20(6)+30=120+30=150$$ $$ herefore$$ Pass % = $$frac{y}{100x} imes100=frac{y}{x}$$ = $$frac{150}{6}=25\%$$ => Ans - (B)
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Substituting it in equation (i), => $$y=20(6)+30=120+30=150$$ $$ herefore$$ Pass % = $$frac{y}{100x} imes100=frac{y}{x}$$ = $$frac{150}{6}=25\%$$ => Ans - (B)