1. Two positive whole numbers are such that the sum of the first and twice the second number is 8 and their difference is 2. The numbers are:
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By: anil on 05 May 2019 02.19 am
Let the numbers be $$x$$ and $$(x-2)$$ According to ques, => $$x+2(x-2)=8$$ => $$x+2x-4=8$$ => $$3x=8+4=12$$ => $$x=frac{12}{3}=4$$ $$ herefore$$ Numbers are = 4, 2 => Ans - (D)
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