1. A student multiplied a number by 5/6 instead of 6/5. What is the percentage error in the calculation?
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By: anil on 05 May 2019 02.18 am
Let the number be 30 When the student multiplied it by 5/6, => original result = $$frac{5}{6} imes 30 = 25$$ When the student multiply it by 6/5, => New result = $$frac{6}{5} imes 30 = 36$$ => Percentage error in calculation = $$frac{(36 - 25)}{36} imes 100$$ = $$frac{1100}{36} = 30.56\%$$ => Ans - (B)
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