1. x and y are two numbers such that their mean proportion is 16 and third proportion is 128. What is the value of x and y?
Write Comment
Comments
By: anil on 05 May 2019 02.17 am
Three numbers a,b,c are in proportion iff $$b^2 = ac$$ where $$b$$ is the mean proportion and $$c$$ is the third proportion Mean proportion of two numbers $$x$$ and $$y$$ = 16 => $$xy = (16)^2 = 256$$ ---------------(i) Third proportion = 128 => $$y^2 = x imes 128$$ -------------(ii) Substituting value of $$x$$ from equation(i) in equation(ii), we get : => $$y^2 = frac{256}{y} imes 128$$ => $$y^3 = (2)^8 imes (2)^7 = (2)^{8 + 7}$$ => $$y = (2)^{frac{15}{3}} = 2^5 = 32$$ Substituting it in equation(i), => $$x = frac{256}{32} = 8$$
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use