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Multiple Choice Questions
1. $$\sqrt{\frac{(1 + tan^{2}A)}{tan^2A}}$$ is equal to
(A): secA
(B): sinA
(C): cosecA
(D): cosA
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By: anil on 05 May 2019 03.29 am
Expression : $$sqrt{frac{(1 + tan^{2}A)}{tan^2A}}$$ $$ecause (sec^2A-tan^2A=1)$$ = $$sqrt{frac{sec^2A}{tan^2A}} = frac{secA}{tanA}$$ = $$frac{1}{cosA} div frac{sinA}{cosA}$$ = $$frac{1}{cosA} imes frac{cosA}{sinA}$$ = $$frac{1}{sinA} = cosecA$$ => Ans - (C)
By: anil on 05 May 2019 03.28 am
Expression : $$sqrt{frac{(1 + tan^{2}A)}{tan^2A}}$$ $$ecause (sec^2A-tan^2A=1)$$ = $$sqrt{frac{sec^2A}{tan^2A}} = frac{secA}{tanA}$$ = $$frac{1}{cosA} div frac{sinA}{cosA}$$ = $$frac{1}{cosA} imes frac{cosA}{sinA}$$ = $$frac{1}{sinA} = cosecA$$ => Ans - (C)
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SSC CHSL 16 Jan 2017 Afternoon Shift
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