1. Find k, if the line 2x - 3y = 11 is perpendicular to the line 3x + ky = 4?
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By: anil on 05 May 2019 02.16 am
Slope of line 2x - 3y = 11 is $$frac{-2}{-3}$$ = $$frac{2}{3}$$ Slope of line 3x + ky = 4 is $$frac{-3}{k}$$ Also, product of slopes of two perpendicular lines is -1 => $$frac{2}{3} imes frac{-3}{k} = -1$$ => $$frac{-2}{k} = -1$$ => $$k = -2 imes -1 = 2$$ => Ans - (D)
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