1. Rohan, after walking 5 km towards west, turns left and then walks for 12 km more. Find the shortest distance between his initial and final position.
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By: anil on 05 May 2019 02.13 am
Let Rohan start from point A walked 5 km towards west to reach point B, then he turns left and then walks for 12 km towards south to reach C. Thus, $$(AC)^2=(AB)^2+(BC)^2$$ => $$(AC)^2=(5)^2+(12)^2$$ => $$(AC)^2=25+144=169$$ => $$AC=sqrt{169}=13$$ km => Ans - (A)
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