1. Two cars travel from city A to city B at a speed of 30 and 44 km/hr respectively. If one car takes 3.5 hours lesser time than the other car for the journey, then the distance between City A and City B is
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By: anil on 05 May 2019 02.10 am
Let the distance between City A and City B = $$d$$ km Speed of first car = 30 km/hr and speed of second car = 44 km/hr
Let time taken by first car = $$t$$ hrs and time taken by second car = $$(t - 3.5)$$ hrs Using, speed = distance/time for first car : => $$frac{d}{t} = 30$$ => $$d = 30t$$ --------------(i) For second car, => $$frac{d}{t - 3.5} = 44$$ Substituting value of $$d$$ from equation (i), we get : => $$30t = 44t - 154$$ => $$44t - 30t = 14t = 154$$ => $$t = frac{154}{14} = 11$$ hrs From equation (i), => $$d = 30 imes 11 = 330$$ km => Ans - (A)
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Let time taken by first car = $$t$$ hrs and time taken by second car = $$(t - 3.5)$$ hrs Using, speed = distance/time for first car : => $$frac{d}{t} = 30$$ => $$d = 30t$$ --------------(i) For second car, => $$frac{d}{t - 3.5} = 44$$ Substituting value of $$d$$ from equation (i), we get : => $$30t = 44t - 154$$ => $$44t - 30t = 14t = 154$$ => $$t = frac{154}{14} = 11$$ hrs From equation (i), => $$d = 30 imes 11 = 330$$ km => Ans - (A)