1. A man walks 20 m towards north, then he turns right and walks 3 m, then turns left and walks 4 m and from there he walks 4 m towards east. How far and in which direction is he from his initial position?
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By: anil on 05 May 2019 02.10 am
Let the man starts from point A and walked 20 m north to reach point B, then he turned right towards east and walked for 3 m, from point C he turned left to reach D after walking 4 m and finally stopped at point E. Thus, AE = $$sqrt{(20+4)^2+(4+3)^2}$$ => $$AE=sqrt{576+49}=sqrt{625}$$ => $$AE=25$$ m Thus, he is 25 m north-east of his original position. => Ans - (B)
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